Yuav ua li cas los xam lub inductance ntawm kuv-zoo li tus inductor core?

Apr 23, 2019

Tso lus

Kuv zoo li tus cwj pwm hauv inductance yog tsim ntawm cov coils, cores thiab lwm yam ntaub ntawv. Hauv kev siv, txoj kev xam ntawm qhov kev ua pa yog ib qho teeb meem tseem ceeb heev. Yuav ua li cas peb yuav tsum xam qhov inductance ntawm I-inductor cores?
Qhov inductance ntawm I-zoo li tus inductor core kuj hu ua self-inductance coefficient, uas yog lub cev ntau kom qhia tau qhov peev xwm ntawm tus kheej inductor. Qhov tshwj xeeb tshaj yog thaum lub suab pauv ntawm ib co co hloov, yuav muaj peev xwm nyob rau hauv lub coil, uas yog qhov phenomenon ntawm electromagnetic induction.
Qhov muab formula ntawm coil nyob rau hauv kuv-zoo li tus inductor core:
Impedance (ohm) = 2 * 3.14159 * F (ua haujlwm ntau dua) * inductance (mH), qhov chaw yuav tsum 360 ohm impedance, yog li
Inductance (mH) = impedance (ohm) (2 * 3.14159) F (ua haujlwm ntau dua) = 360 (2 * 3.14159) 7.06 = 8.116 mH.
Yog li peb yuav xam cov naj npawb ntawm winding coils raws li cov ntaub ntawv tau txais, uas yog:
Pes tsawg ntawm cov zauv = inductance * {(18 * lub voj voj voj (inch) + (40 * voj voog ntev (nti)}] lub voj voos kab (inch).
Tus nab npawb ntawm kev = = 8.116 * {(18 * 2.047) + (40 * 3.74)}] 2.047 = 19 cycles.
Cov qauv ntawm kev xam cov khoob khoob khawm hauv qhov tseem ceeb yog L (mH) = (0.08DDNN) / (3D + 9W + 10H).
Ntawm lawv:
D stands rau lub kauj puv npo, N cim rau kauj puv, D stands rau txoj kab uas h, H stands rau kev ntsuas qhov siab, W sawv rau kauj dav dav hauv millimeters thiab mH, feem.
Yog li, qhov formula rau xam qhov inductance ntawm air-core coil yog: l = (0.01 * D * N * N) / (L / D + 0.44).

Yog xav paub ntxiv, thov hu rau peb ntawm sales@xfullstar.com

Xa kev nug